Answer 3
note instead of using scientific notation, it is replaced with "e"
2.95e-6 M NaOH
[H+]
10^(-8.47) =
3.39e-9 |
[OH-]
Molarity of a Base = [OH-]
2.95e-6 |
pH
14 - 5.53 =
8.47 |
pOH
-log(2.95e-6) =
5.53 |